7h^2+7h-7=0

Solution for 7h^2+7h-7=0 equation:

7h^2+7h-7=0

a = 7; b = 7; c = -7;
Δ = b2-4ac
Δ = 72-4·7·(-7)
Δ = 245
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{245}=\sqrt{49*5}=\sqrt{49}*\sqrt{5}=7\sqrt{5}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7\sqrt{5}}{2*7}=\frac{-7-7\sqrt{5}}{14}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7\sqrt{5}}{2*7}=\frac{-7+7\sqrt{5}}{14}
$